Anders and Briegel in Python
25'ten fazla konu seçemezsiniz Konular bir harf veya rakamla başlamalı, kısa çizgiler ('-') içerebilir ve en fazla 35 karakter uzunluğunda olabilir.

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  1. import json
  2. import numpy as np
  3. from abp import clifford, qi
  4. import sys
  5. import os
  6. import itertools as it
  7. from string import maketrans
  8. def get_ab_cz_table():
  9. """ Load anders and briegel's CZ table """
  10. filename = "anders_briegel/cphase.tbl"
  11. filename = os.path.join(os.path.dirname(sys.path[0]), filename)
  12. with open(filename) as f:
  13. s = f.read().translate(maketrans("{}", "[]"))
  14. return np.array(json.loads(s))
  15. def test_cz_table():
  16. """ Does our clifford code work with anders & briegel's table? """
  17. state_table = clifford.get_state_table(clifford.unitaries)
  18. ab_cz_table = get_ab_cz_table()
  19. rows = it.product([0, 1], it.combinations_with_replacement(range(24), 2))
  20. for bond, (c1, c2) in rows:
  21. # Pick the input state
  22. input_state = state_table[bond, c1, c2]
  23. # Go and compute the output
  24. computed_output = np.dot(qi.cz, input_state)
  25. computed_output = qi.normalize_global_phase(computed_output)
  26. # Now look up the answer in the table
  27. bondp, c1p, c2p = ab_cz_table[bond, c1, c2]
  28. table_output = state_table[bondp, c1p, c2p]
  29. assert np.allclose(computed_output, table_output)
  30. def _test_match():
  31. """ Tests that they actually match """
  32. ab_cz_table = get_ab_cz_table()
  33. rows = it.product([0, 1], it.combinations_with_replacement(range(24), 2))
  34. for bond, (c1, c2) in rows:
  35. assert np.all(ab_cz_table == clifford.cz_table)